The equivalent conductance `(Lambda_(eq.))` is given by the relation

The unit of equivalent conductivity (Lambda_(eq.)) are

The specific conductance (kappa) of an electrolyte of 0.1 N concentration is related to equivalent conductance (Lambda_(e)) by the following formula :

Conductors allow the passage of electric current through them. Metallic and electrolytic are the two type of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or consuctivity of the electrolyte solution is given by the following relation : kappa=c xx l/A where, c=1//R is the conductance and l//A is the cell constant. Molar conductance (Lambda_(m)) and equivalence conductance (Lambda_(e)) of an electrolyte solution are calculated using the following similar relations : Lambda_(m)= kappa xx 1000/M Lambda_(e)= kappa xx 1000/N Where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : Lambda_(m)=Lambda_(m)^(@)-b sqrt(c) where, Lambda_(m)^(@)= molar conductance at infinite dilution c= concentration of the solution b= constant The degrees of dissociation of weak electrolytes are calculated as : alpha=Lambda_(m)/Lambda_(m)^(@)=Lambda_(e)/Lambda_(e)^(@) The correct order of equivalent conductances at infinite dilution of LiCl, NaCl and KCl is :

Conductors allow the passage of electric current through them. Metallic and electrolytic are the two type of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or consuctivity of the electrolyte solution is given by the following relation : kappa=c xx l/A where, c=1//R is the conductance and l//A is the cell constant. Molar conductance (Lambda_(m)) and equivalence conductance (Lambda_(e)) of an electrolyte solution are calculated using the following similar relations : Lambda_(m)= kappa xx 1000/M Lambda_(e)= kappa xx 1000/N Where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : Lambda_(m)=Lambda_(m)^(@)-b sqrt(c) where, Lambda_(m)^(@)= molar conductance at infinite dilution c= concentration of the solution b= constant The degrees of dissociation of weak electrolytes are calculated as : alpha=Lambda_(m)/Lambda_(m)^(@)=Lambda_(e)/Lambda_(e)^(@) The conductance of a solution of an electrolyte is equal to that of its specific conductance. The cell constant of the conductivity cell is equal to :

The specific conductance ( kappa ) of an electrolyte of 0.1 N concentration is related to equivalent conductance ( Lambda e ) by the following formula

Which of the following expressions correctly repesents the equivalent conductance at infinte dilution of Al_(2)(SO_(4))_(3) . Given that Lambda_(Al^(3+))^(@) and Lambda_(SO_(4)^(2-))^(@) are the equivalent conductance at infinte dilution of the respective ions?

At infinite dilution, the equivalent conductivity of the electrolyte is given by the expression: ^^^_(eq)^(oo)=lambda_((+))^(oo)+lambda_((-))^(oo) The above expression is given by

At infinite dilution, the equivalent conductivity of the electrolyte is given by the expression: ^^^_(eq)^(oo)=lambda_((+))^(oo)+lambda_((-))^(oo) The above expression is given by

Solubility of a sparingly soluble salt S , specific conductance K , and the equivalent conductance Lambda_(0) are related as