[" In a Young's double slit experiment "lambda=500nm" ,"],[d=1*0mm" and "D=1*0m" .Find the minimum distance "],[" from the central maximum for which the intensity is "],[" half of the maximum intensity."]

In a Young's double slit experiment lamda= 500nm, d=1.0 mm andD=1.0m . Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.

In a Young's double slit experiment lamda= 500nm, d=1.0 mm andD=1.0m . Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.

In a Young's double slit experiment lamda= 500nm, d=1.0 mm andD=1.0m . Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.

In Young's double-slit experiment lambda = 500 nm, d = 1 mm , and D = 4 m . The minimum distance from the central maximum for which the intensity is half of the maximum intensity is '**' xx 10^(-4) m . What is the value of '**' ?

In Young's double-slit experiment lambda = 500 nm, d = 1 mm , and D = 4 m . The minimum distance from the central maximum for which the intensity is half of the maximum intensity is '**' xx 10^(-4) m . What is the value of '**' ?

In a Young's double-slit experiment, lambda=500nm . d=1nm and D=1m .The minimum distance from the central maximum,at which the intensity is half of the maximum intensity,is x times10^(-4)m .The value of x is(---) .

In a Young's double slit experiment,two slits are 1.5 mm apart and a screen in placed at a distance 1.2 m from the plane of the slits .The slits are illuminated with light of wavelength 6,000 overset @A .Find the inimum distance from the central maximum for which the intensity is half of the maximum intensity.

In a double experiment D=1m, d=0.2 cm and lambda = 6000 Å . The distance of the point from the central maximum where intensity is 75% of that at the centre will be: