[20.cos20.cos40.cos60.cos80=],[[" A) "1,...

[20.cos20.cos40.cos60.cos80=],[[" A) "1," B) "1/14," C) "1/16," D) "1/11]]

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cos20^@cos40^@cos80^@=

cos20^(@).cos40^(@).cos60^(@).cos80^(@) is :

cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16

cos20^(@).cos40^(@).cos60^(@).cos80^(@)=1/16

cos 20^@.cos 40^@.cos 60^@ cos 80^@= a) 1/16 b) 3/16 c) sqrt3/16 d) sqrt3/32

Show that cos20^o cos40^o cos60^o cos80^o =1/16

cos20 ^ (@) cos40 ^ (@) cos60 ^ (@) cos80 ^ (@) - (1) / (16) =

Prove that cos 20^@cos 40^@cos 60^@cos 80^@=1/16 .

cos20^(0)cos40^(0)cos60^(0)cos80^(0) is equal to

Prove that, cos20^@cos40^@cos60^@cos80^@=1/16

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