`(2sintheta-sin2theta)/(2sintheta+sin2theta)=tan^2(theta/2)`

sintheta+sin2theta+sin4theta+sin5theta=0

(sintheta+sin2theta)/(1+costheta+cos2theta)

(sintheta+sin2theta)/(1+costheta+cos2theta)

(sintheta+sin2theta)/(1+costheta+cos2theta) =

(sintheta+sin2theta)/(1+costheta+cos2theta)=?

(sintheta+sin 2theta)/(1+costheta+cos2theta)=

Given that 1-costheta=2sin^2(theta/2) and 1+costheta=2cos^2(theta/2) prove that (1+sintheta-costheta)/(1+sintheta+costheta)=tan(theta/2)

Prove that (sintheta +sin2theta)/(1+costheta +cos2theta)=tantheta

If sintheta=(12)/(13) , find the value of (sin^2theta-cos^2theta)/(2sinthetacostheta)xx1/(tan^2theta)

Prove that : (sintheta +sin2theta)/(1+costheta+cos2theta)=tantheta