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(1+sintheta)/(1-sintheta)=tan^2(pi/4+the...

`(1+sintheta)/(1-sintheta)=tan^2(pi/4+theta/2)`

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Show that (1+tan .theta/2)/(1-tan. theta/2)=(1+sintheta)/(cos theta)=tan(pi/4+theta/2)

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(1+sintheta)/(1-sintheta)=1+(2tantheta)/costheta+2tan^2theta .