Estimate the amount of energy released in the nuclear fusion reaction:
`_(1)H^(2)+._(1)H^(2)rarr._(2)He^(2)+._(0)n^(1)` Given that
`M(._(1)H^(2))=2.0141u, M(._(2)He^(3))=3.0160u`
`m_(n)=1.0087u` ,
where `1u=1.661xx10^(-27)kg` .
Express your answer in units of MeV.

Calculate the energy of the following nuclear reaction: ._(1)H^(2)+._(1)H^(3) to ._(2)He^(4) + ._(0)n^(1)+Q Given: m(._(1)H^(2))=2.014102u, m(._(1)H^(3))=3.016049u, m(._(2)He^(4))=4.002603u, m(._(0)n^(1))=1.008665u

Calculate the energy released in the following: ._(1)H^(2) + ._(1)H^(3) rarr ._(2)He^(4) + ._(0)n^(1) (Given masses : H^(2) = 2.014, H^(3) = 3.016, He = 4.003, n = 1.009 m_(u))

Calculate the energy released in the following: ._(1)H^(2) + ._(1)H^(3) rarr ._(2)He^(4) + ._(0)n^(1) (Given masses : H^(2) = 2.014, H^(3) = 3.016, He = 4.003, n = 1.009 m_(u))

Calculate the energy released in the following nuclear reaction: ""_(1)^(2)H+ ""_(1)^(2)H =""_(2)^(4)He Mass of ""_(1)^(2)H = 2.01419u, Mass of ""_(2)^(4)He =4.00277u

Energy released in the nuclear fusion reaction is : ""_(1)^(2)H + ""_(1)^(3)H rarr ""_(2)^(4)He + ""_(0)^(1)n Atomic mass of ""_(1)^(2)H=2.014 , ""_(1)^(3)H=3.016 ""_(2)^(4)He=4.303, ""_(0)^(1)n=1.009 (all in a.m.u.)

Calculate the energy in fusion reaction: ""_(1)H^(2) + ""_(1)H^(2) to ""_(2)He^(3) + ""_(0)n^(1) , where B.E. Of ""_(1)H^(2) = 2.23 MeV and ""_(2)He^(3) = 7.73 MeV.

Extimate the amount of energy released in the following nuclear fusion reaction. overset(2)(1)H+overset(2)(1)Hrightarrowoverset(3)(2)He+overset(1)(0)n Given mass of overset(2)(1)H=2.0141 amu, mass of overset(3)(2)He=3.0160 amu, mass of overset(1)(0)n=1.0087 amu and 1 amu = 1.661xx10^(-27)kg . Express your answer in units of MeV?