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cot 6^0 cot 42^0 cot 66^0 cot 78^0=1...

`cot 6^0 cot 42^0 cot 66^0 cot 78^0=1`

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If A =tan6^0tan42^0 and B=cot66^0cot78^0 , then

cot16^0cot44^0+cot44^0cot76^0-cot76^0cot16^0 = (a) 1 (b) 2 (c) 3 (d) 4

cot16^0cot44^0+cot44^0cot76^0-cot76^0cot16^0 = (a) 1 (b) 2 (c) 3 (d) 4

cot16^0cot44^0+cot44^0cot76^0-cot76^0cot16^0 = (a) 1 (b) 2 (c) 3 (d) 4

Prove that: t a n 225^0cot 405^0+t a n 765^0cot 675^0=\ 0

If A = tan 6^@ tan 42^@ and B = cot 66^@ cot 78^@, then

cot16^(0)cot44^(0)+cot44^(0)cot76^(0)-cot76^(0)cot16^(0)

cot16^(0)cot44^(0)+cot44^(0)cot76^(0)-cot76^(0)cot16^(0)=(a)1(b)2(c)3(d)4

If A=tan6^(@) tan42^(@), B=cot66^(@) cot78^(@) then