सत्यापन कीजिए `f(x)=x-2 sin x,` अन्तराल [`-pi, pi`].

If f(x)=x sin x then f'(pi/2) = ……

f:[-3 pi,2 pi]f(x)=sin3x

If f(x)=(e^(x)+e^(-x)-2)/(x sin x) , for x in [(-pi)/(2), (pi)/(2)]-{0} , then for f to be continuous in [(-pi)/(2), (pi)/(2)], f(0)=

If f(x)=(e^(x)+e^(-x)-2)/(x sin x) , for x in [(-pi)/(2), (pi)/(2)]-{0} , then for f to be continuous in [(-pi)/(2), (pi)/(2)], f(0)=

f(x) = sin x is a strictly decreasing in (pi/2,pi)

If : f(x) {:(=x.sin x ", ... " 0 lt x le pi/2),(=pi/2 sin (pi+x)", ... "pi/2ltxltpi):} , then

Let f(x)=|x|+|sin x|, x in (-pi//2,pi//2). Then, f is

Let f(x)=|x|+|sin x|, x in (-pi//2,pi//2). Then, f is