In a diamond, carbon atom occupy fcc lattice points as well as alternate tetrahedral voids. If edge length of the unit cell is 356pm, then diameter of carbon atom is:

In diamond, carbon atoms occupy fcc lattice points as well as alternate tetrahedral voids. If edge length of the unit cell is 356 pm, the diameter of carbon atoms is

An element crystallizes in a structure having FCC unit cell of an edge length of the unit cell is 286pm, the radius of iron atom is

In a diamond, each carbon atom is bonded to four other carbon atoms tetrahedrally. Alternate tetrahedral voids are occupied by carbon atoms. The number of carbon atoms per unit cell is:

In a diamond, each carbon atom is bonded to four other carbon atoms tetrahedrally. Alternate tetrahedral voids are occupied by carbon atoms. The number of carbon atoms per unit cell is:

In a diamond, each carbon atom is bonded to four other carbon atoms tetrahedrally. Alternate tetrahedral voids are occupied by carbon atoms. The number of carbon atoms per unit cell is:

Number of tetrahedral voids occupied in a unit cell of diamond is

Number of tetrahedral voids occupied in a unit cell of diamond is

a metal crystallizes with a face-centered cubic lattice.The edge of the unit cell is 408 pm. The diameter of the metal atom is :

A Metal crystallizes in fcc lattice and the edge of the unit cell is 620 pm. The radius of metal atom is