The direction cosines of a normal to the plane `2x-3y-6z+14=0` are (A) `(2/7,(-3)/7,(-6)/7)` (B) `((-2)/7,3/7,6/7)` (C) `((-2)/7,(-3)/3,(-6)/7)` (D) none of these

Find the direction cosines of the normal to the plane is (3x-6y+2z=7 .

The direction cosines of the ray from (0,0,0) to (2,-3,6) are (A) -2/7,3/7,-6/7 (B) 2/7,37,6/7 (C) -2/7,-3/7,6/7 (D) 2/7,-3/7,6/

The direction cosines of the ray from (0,0,0) to (2,-3,6) are (A) -2/7,3/7,-6/7 (B) 2/7,37,6/7 (C) -2/7,-3/7,6/7 (D) 2/7,-3/7,6/

If projections of as line on x,y and z axes are 6,2 and 3 respectively, then directions cosines of the lines are (A) (6/2,2/7,3/7) (B) (3/5,5/7,6/7) (C) (1/7,2/7,3/7) (D) none of these

If projections of as line on x,y and z axes are 6,2 and 3 respectively, then directions cosines of the lines are (A) (6/2,2/7,3/7) (B) (3/5,5/7,6/7) (C) (1/7,2/7,3/7) (D) none of these

The distasnce of the plane 2x-3y+6z+14=0 from the origin is (A) 2 (B) 4 (C) 7 (D) 11

The distasnce of the plane 2x-3y+6z+14=0 from the origin is (A) 2 (B) 4 (C) 7 (D) 11

O is origin and P is a point at a distance of 7 units from origin if the direction ratios of OP are lt 3 ,-2, 6 gt , then the coordinates of P are (i) (3,-2,6) (ii) (21,-14,42) (iii) (3/7,-2/7,6/7) (iv) none of these

The projections of a vector on the three coordinate axis are 6,3,2 respectively.The direction cosines of the vector are (A)6,-3,2(B)(6)/(5),(-3)/(5),(2)/(5)(C)(6)/(7),(6)/(7),(2)/(7) (D) (-6)/(7),(-3)/(7),(2)/(7)