The energy of a photon is given by E `= (hc)/(lambda)`
If `lambda=4xx10^(-7`)m,the energy of photon is

The energy of a photon of wavelength lambda is

The energy of a photon of wavelength lambda is given by

If the energy of a photon is given by E =(hc)/(lambda) , where h is the Plank's constant c is the velocity of light and lambda is the wavelength of the radiation then the unit of Planck's constant is "______"

The energy of a photon of wavelength lambda is—

The energy of photon of wavelength lambda is

The energy of a photon in eV of wavelength lambda nm will be

The energy of a photon is E = hv and the momentum of photon p = (h)/(lambda) , then the velocity of photon will be

The energy of a photon of frequency 4 xx 10^(15) Hz is ?