" If eorix "+cos beta=a_(2)sin alpha+sin beta=b" and "alpha-beta=20," then "(cos30)/(cos theta)=

If cos alpha+cos beta=a*sin alpha+sin beta=b and alpha-beta=2 theta then (cos3 theta)/(cos theta)=

Ifcos alpha+cos beta=a,sin alpha+sin beta=b and alpha-beta=2 theta then (cos3 theta)/(cos theta)=

If cos alpha+ cos beta= a, sin alpha+ sin beta= b and alpha- beta= 2 theta . Then (cos 3 theta)/(cos theta)=

If cos alpha+cos beta=a sin alpha+sin beta=balpha-beta=2 theta then (cos3 theta)/(cos theta)=

If cos a+cos beta=a,sin a+sin beta=b are alpha-beta=2 theta, then (cos3 theta)/(cos3 theta)=

If sin alpha+sin beta=a and cos alpha-cos beta=b then

If sin alpha+sin beta=a and cos alpha-cos beta=b then tan((alpha-beta)/(2))=

If cos alpha+cos beta=0=sin alpha+sin beta then cos2 alpha+cos2 beta=

If sin alpha + sin beta = a , cos alpha + cos beta = b " then cos ( alpha + beta ) =