The distance of the point `theta` on the ellipse `x^2/a^2+y^2/b^2=`1 from a focus is

The distance of a point on the ellipse x^2/6 + y^2/2 = 1 from the centre is 2. Find the eccentric angle of the point.

The sum of the distances of any point on the ellipse 3x^(2)+4y^(2)=24 from its foci is

The sum of the distances of any point on the ellipse 3x^(2)+4y^(2)=24 from its foci is

The sum of the distances of any point on the ellipse 3x^(2) + 4y^(2) = 24 from its foci , is

The distance of a point on the ellipse (x^(2))/(6)+(y^(2))/(2)=1 from the centre is 2 Then the eccentric angle of the point is

Find the focal distance of point P(theta) on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1

If the distance of a point on the ellipse (x^(2))/(6) + (y^(2))/(2) = 1 from the centre is 2, then the eccentric angle of the point, is

The sum of the distances of any point on the ellipse 3x^(2)+4y^(2)=12 from its directrix is

The distance of a point on ellipse (x^(2))/(6) + (y^(2))/(2) = 1 from its centre is sqrt(2) . The eccentric is sqrt(2) angle of the point will be

The maximum distance of the centre of the ellipse (x^(2))/(81)+(y^(2))/(25)=1 from a normal to the ellipse is