`int((x^(2)+2)d)/(x+1)x`

(i) int((x^(2) - 1)/(x^(2) + 1))dx , (ii) int ((x^(6)- 1)/(x^(2) + 1))dx (iii) int ((x^(4))/(1+x^(2)))dx , (iv) int((x^(2))/(1+x^(2)))dx

int(x^(2)dx)/((x^(2)-1)(x^(2)+2))=

int((x+1)^2)/x d x

int(x^(2))/((x^(2)-1)(x^(2)+2))dx

int(2x^(2)+x-2)/(x^(2)+1)dx

int x^(2)sqrt(x+2)dx(ii)int(x^(2))/(sqrt(x-1))dx

(d)/(dx) int_(2)^(x^(2)) (t -1) dt is equal to

int((1+x)^(2))/(x(1+x^(2)))dx=

Evaluate : "int((x^(2)-x+1))/((x^(2)+1))dx

Evaluate : int(x^(2)-1)/((x+1)(x+2))dx