A tangent to `y^(2)=5x` is parallel to the line y=4x+1 .Then the point of contact is

If the tangent to the curve y=6x-x^2 is parallel to line 4x-2y-1=0, then the point of tangency on the curve is

Find the point on the curve y=x^(4)-6x^(3)+13x10x+5, where the tangent is parallel to the line.y=2x .Show that two of these points have the same tangent.

If 4x-3y=sqrt(3) is a tangent to 4x^(2)-9y^(2)=1 , Then the eccentric angle of the point of contact is

The tangent to the curve y=x^(2)-5x+5 . parallel to the line 2y=4x+1, also passes through the point: