The rate of change of displacement with respect to time is known as velocity.If displacement of a particle is s=3t^(2)+4t+5 then velocity as a function of time

If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the velocity of particle at t=2 is

If displacement S at time t is S=2t^(3) +6t , then velocity is always

If displacement S at time t is S=10t-5t^(2) , then velocity at time t is

If displacement of particle is s=t^(3)-6t^(2)+9t+15, then velocity of the particle at beginning is

If displacement S at time t is S=-t^(3)+3t^(2)+5 , then velocity at time t=2 sec is

If the displacement of a particle varies with time as x = 5t^2+ 7t . Then find its velocity.

The displacement s of a particle at time t is given by s = t^3 -4 t^2 -5t. Find the velocity and acceleration at t=2 sec

If displacement of particle is s=(t^(3))/(3)-(t^(2))/(2)-(t)/(2)+6 , then velocity of the particle at t=4 sec. is

The displacement of a particle at time t is given by s= 2t^(3) -5t^(2)+ 4t-3 . Find the velocity when t = 2 sec.

A particle moves with an initial velocity v_(0) and retardation alphav, where alpha is a constant and v is the velocity at any time t. If the particle is at the origin at t=0 , find (a) (i) velocity as a function of time t. (ii) After how much time the particle stops? (iii) After how much time velocity decreases by 50% ? (b) (i) Velocity as a function of displacement s. (ii) The maximum distance covered by the particle. (c ) Displacement as a function of time t.