`x^2+10^-8 x-10^-14=0` How to solve ?

x^(4)+8x^(3)+9x^(2)-8x-10=0 Solve for x

The locus of the centre of a circle which touches externally the circle x^2 + y^2-6x-6y+14 = 0 and also touches Y-axis, is given by the equation (a) x^2-6x-10y+14 = 0 (b) x^2-10x-6y + 14 = 0 (c) y^ 2-6x-10y+14-0 (d) y^2-10x-6y + 14 = 0

The locus of the centre of a circle which touches externally the circle x^2 + y^2-6x-6y+14 = 0 and also touches Y-axis, is given by the equation (a) x^2-6x-10y+14 = 0 (b) x^2-10x-6y + 14 = 0 (c) y^2+6x-10y+14-0 (d) y^2-10x-6y + 14 = 0

The locus of the centre of a circle which touches externally the circle x^2 + y^2-6x-6y+14 = 0 and also touches Y-axis, is given by the equation (a) x2-6x-10y+14 = 0 (b) x2-10x-6y + 14 = 0 (c) yr_6x-10y+14-0 (d) y,2-10x-6y + 14 = 0

Solve x^(2) - 10x + 21= 0

The locus of the centre of a circle which touches externally the circle x^(2)+y^(2)-6x-6y+14=0 and also touches Y-axis,is given by the equation (a) x2-6x-10y+14=0 (b) x2-10x-6y+14=0 (c) yr 6x-10y+14-0 (d) y,2-10x-6y+14=0

Solve the equation x^2-3x-10=0 by using formula.

Solve the equation x^2-3x-10=0 by using formula.