`"Tan"^(-1)(cosx)/(1+sinx)=`

tan^-1((1+cosx)/(sinx))

Find (dy)/(dx) for y=tan^(-1){(1-cosx)/(sinx)}.

"tan"^(-1)(1+sinx)/(cosx)=

Find (dy)/(dx) for y=tan^(-1){(1-cosx)/(sinx)},-piltxltpi

If y=tan^(-1)((1-cosx)/(sinx)), then (dy)/(dx) is

Find (dy)/(dx) for y=tan^(-1){(1-cosx)/(sinx)},-piltxltpi .

If y=tan^(-1)((1-cosx)/(sinx)), then (dy)/(dx) is

If y=tan^(-1)((1-cosx)/(sinx)), then (dy)/(dx) is

If y=tan^(-1)((1-cosx)/(sinx)), then (dy)/(dx) is

Differentiate each of the following w.r.t. x: (i) tan^(-1)((1-cosx)/(sinx))" "(ii)tan^(-1)((cos x -sinx)/(cosx +sinx))