A particle of mass m movies along a curve `y=x^(2)`. When particle has x-co-ordinate as `1//2` and x-component of velocity as `4 m//s`. Then :-

A particle of mass m moves along a curve y=x^2 . When particle has x-coordinate as (1)/(2) m and x-component of velocity as 4(m)/(s) , then

A particle of mass m moves along a curve y=x^2 . When particle has x-coordinate as (1)/(2) m and x-component of velocity as 4(m)/(s) , then

A particle of mass 1kg moves along the curve y=x^(2) Magnitude of angular momentum of the particle about origin,when particle has x co-ordinate is (1)/(2)m and x-component of velocity is 4m/s is

A particle moves along a path y = ax^2 (where a is constant) in such a way that x-component of its velocity (u_x) remains constant. The acceleration of the particle is

A particle moves along a path y = ax^2 (where a is constant) in such a way that x-component of its velocity (u_x) remains constant. The acceleration of the particle is

A particle moves along a parabolic path y=-9x^(2) in such a way that the x component of velocity remains constant and has a value 1/3m//s . Find the instantaneous acceleration of the projectile (in m//s^(2) )

A particle moves along a parabolic path y=-9x^(2) in such a way that the x component of velocity remains constant and has a value 1/3m//s . Find the instantaneous acceleration of the projectile (in m//s^(2) )

A particle moves along a parabolic parth y = 9x^(2) in such a way that the x-component of velocity remains constant and has a value 1/3 ms ^(-1) . The acceleration of the particle is -

A particle moves along a parabolic parth y = 9x^(2) in such a way that the x-component of velocity remains constant and has a value 1/3 ms ^(-1) . The acceleration of the particle is -

A particle moves along "x" -axis with an acceleration a=12x^(2)ms^(-2) .The particle has zero velocity at "x=(-2)m" .Find the velocity of the particle (in m/sec)as it passes through origin.