ABCD is a quadrilateral whose diagonals are AC and BD. Which one of the following is correct?

If ABCD is a quadrilateral whose diagonals AC and BD intersect at O, then

ABCD is a rhombus with diagonals AC and BD. Then which one among the following is correct ?

ABCD is a quadrilateral whose diagonals AC and BD intersect at O, prove that: (AB+BC+CD+DA)>(AC+BD)

ABCD is a quadrilateral whose diagonals AC and BD intersect at O, prove that: (AB+BC+CD+DA)>2(AC+BD)

ABCD is a quadrilateral whose diagonals AC divides it into two parts, equal is area. Then, ABCD is

In the adjoining figure, ABCD is a quadrilateral. Its diagonals AC and BD intersect at point 'O'. Prove that : (a) AB+BC+CD+DA lt 2(AC+BD) (b) AB+BC+CD+DA gt (AC+BD)

In the adjoining figure, ABCD is a quadrilateral. Its diagonals AC and BD intersect at point 'O'. Prove that : (a) AB+BC+CD+DA lt 2(AC+BD) (b) AB+BC+CD+DA gt (AC+BD)

ABCD is a quadrilateral whose diagonal AC divides it into two parts, equal in area, then ABCD