If |z1|=|z2| and arg(z1)+arg(z2)=pi/2 th...

If `|z_1|=|z_2|` and `arg(z_1)+arg(z_2)=pi/2` then
(A) `z_1z_2` is purely real
(B) `z_1z_2` is purely imaginary
(C) `(z_1+z_2)^2` is purely imaginary
(D) `arg(z_1^(-1))+arg(z_2^(-1))=-pi/2`

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