[" Find the length. "],[" 4.त्रिभुज "ABC" Arm of "BC" A point on "D" Is as follows "/_ADC=/_BAC" .दिखाएँ That "],[CA^(2)=CB*CD]

D is a point on the side BC of a triangle ABC /_ADC=/_BAC Show that CA^(2)=CB.CD

D is a point on the side BC of a triangle ABC such that /_ADC= /_BAC . Show that CA^(2)= CB*CD .

D is a point on the side BC of DeltaABC . If /_ADC=/_BAC , then prove that CA^(2)=CBxxCD .

In the figure in DeltaABC, point D on side BC is such that /_BAC=/_ADC . Prove that CA^(2)=CBxxCD .

In the given figure , D is a point on the side BC of Delta ABC such that angle ADC=angle BAC . Prove that CA^(2)=CBxxCD .

D is a point on the side BC of a triangle ABC such that angleADC=angleBAC . Show CA^(2)=CB.CD

In the given fig DeltaDGH~DeltaDEF, DH=8cm, DF=12cm, DG=(3x-1) cm and DE=(4x+2) cm, Find the lengths of DG and DE. OR D is a point on the side BC of DeltaABC such that lfloorADC=lfloorBAC . Prove that (CA)/(CD)=(CB)/(CA) .

D is a point on the side BC of ABC such that /_ADC=/_BAC. Prove that (CA)/(CD)=(CB)/(CA) or,CA^(2)=CB xx CD

D is a point on the side BC of a triangle ABC such that angleADC=angleBAC .Show that CA^2=CB.CD .

AD is the bisector of /_BAC of /_\ABC , where D is a point on BC. Prove that (BD)/(DC)=(AB)/(AC) .