The displacement of a simple harmonic oscillator is, x = 5 sin `(pit//3) m`. Then its velocity at t = 1 s, is

The displacement of a simple harmonic oscillator is x = 5 sin (pi t /3) m . Then its velocity at t =1 s , is

The displacement of a simple harmonic oscillator is given by x = 4 cos (2pit+pi//4)m . Then velocity of the oscillator at t = 2 s is

The displacement of a simple harmonic oscillator is given by y= 0.40 sin (440t +0.61) . For this, what are the value of amplitude.

Equation of displacement of a harmonic oscillator is x =15 sin 20 pit , amplitude and angular velocity are respectively

The displacement of a particle executing S.H.M. is x = 5 sin (20 pit ). Then its frequency will be

The displacement of a particle executing S.H.M. is x = 5 sin (20 pit ). Then its frequency will be

When the displacement of a simple harmonic oscillator is half of its amplitude, its potential energy is 3J. Its total energy is

The displacement of a linear simple harmonic oscillator is given by y = "sin"(pi)/(2)[(t)/(2)+(1)/(2)] cm. The maximum acceleration of the oscillator in cms^(-2) is

The displacement equation of an oscillator is given by x = 5 sin (2pit+0.5pi)m . Then its time period and initial displacement are