" 杜 "(3x-1)/((x+2)^(2))

Simplify : ((x^(2)-1)/((x^(2)-3x+2)))xx((x-2)/(x+1))

(3x-2)/((x +1) ^(2) (x +2))=(A)/(x+1) + (B)/((x +1)^(2))+ (C )/(x +3), then A + B+C =

(3x - 9)/( (x - 1 )(x + 2 )(x^(2)+1))

(log (x^(3) + 3x^(2) + 3x + 1))/(log (x^(2) + 2x + 1)) is equal to

(i) (2x+3) (3x-5) (ii) x(1+x)^(3) (iii) (sqrtx + 1/x) (x -1/sqrtx) (iv) (x-1/x)^(2) (v) (x^(2) + 1/x^(2))^(3) (vi) (2x^(2) +5x-1) (x-3)

Resolve (3x^(2)+1)/((x^(2)-3x+2)(2x+1)) into partial fractions.