" い 6."(x^(2)-5x)^(2)-30(x^(2)-5x)-216=0

(x^(2)-5x-6)/(x^(2)+3x+2)

Two non-integer roots of (x^(2) - 5x)^(2) - 7 (x^(2) - 5x) + 6 = 0 are

x^(2)-5x+6>0

The number of real roots of the equation (x^(2)+5x+6)^(2)+5(x^(2)+5x+6)+6-x=0 is

Solve by the method of completing the square: (1) 9x^(2)-15x+6=0 (2) 5x^(2)-6x-2=0

The roots of 6x^(4) - 5x^(3) - 38x^(2) - 5x + 6 = 0 are

int(x^(3)-6x^(2)+10x-2)/(x^(2)-5x+6)dx=

Solve the inequality: (x^(2)-1)/(x^(2)+1)+x^(2)-5x+6<0

Solve the following equations. (x^2 - 5x)^2 - 7 (x^2-5x) div 6=0 .

From the points (3,4), chords are drawn to the circle x^(2)+y^(2)-4x=0 .The locus of the midpoints of the chords is (a) x^(2)+y^(2)-5x-4y+6=0(b)x^(2)+y^(2)+5x-4y+6=0(c)x^(2)+y^(2)-5x+4y+6=0(d)x^(2)+y^(2)-5x-4y-6=0