" 16."(log x)^(2)

The number of real values of the parameter k for which (log_(16)x)^(2) = log_(16) x+ log_(16) k = 0 with real coefficients will have exactly one solution is

The number of real values of the parameter k for which (log_(16)x)^(2) - log_(16) x+ log_(16) k = 0 with real coefficients will have exactly one solution is

Let 1 le x le 256 and M be the maximum value of (log_(2)x)^(4)+16(log_(2)x)^(2)log_(2)((16)/(x)) . The sum of the digits of M is :

Let 1 le x le 256 and M be the maximum value of (log_(2)x)^(4)+16(log_(2)x)^(2)log_(2)((16)/(x)) . The sum of the digits of M is :

Integral value of x which satisfies the equation =log_6 54+(log)_x 16=(log)_(sqrt(2))x-(log)_(36)(4/9)i s ddot

Integral value of x which satisfies the equation =log_6 54+(log)_x 16=(log)_(sqrt(2))x-(log)_(36)(4/9)i s ddot

Integral value of x which satisfies the equation =log_6 54+(log)_x 16=(log)_(sqrt(2))x-(log)_(36)(4/9)i s ddot

The number of real values of the parameter k for which the equation ("log"_(16)x)^(2) -"log"_(16)x +"log"_(16) k = 0 with real coefficients will have exactly one solution, is

int_(0)^(16)(log_(e )x^(2))/(log_(e )x^(2)+log_(e )(x^(2)-44x+484))dx is equal to