Solid `Ca(HCO_(3))_(2)` decomposes as
`Ca(HCO_(3))_(2)(s)hArrCaCO_(3)(s)+CO_(2)(g)+H_(2)O(g)`
If the total pressure is `0.2` bat at `420 K,` what is the standard free energy change for the given reaction `(Delta_(r)G^(@))` ?

NaHCO_3 decomposes into: 2NaHCO_(3(s)) hArrNa_(2)CO_(3(s))+CO_(2(g))+H_(2)O_((g)) The equilibrium pressure is 1.04 atm the K_(p) for the reaction is

Ca(HCO_3)_2 decomposes as Ca(HCO3)2(s)→CaCO3 (s)+H2O (g)+CO2 (g). Total pressure at equilibrium is found to be 0.12 bar. Thus, Kp is ?

The free energy change for the following reactions are given below C_(2)H_(2)(g)+(5)/(2)O_(2)(g)to2CO_(2)(g)+H_(2)O(l) , DeltaG^(@)=-1234 kJ C(s)+O_(2)(g)toCO_(2)(g) , DeltaG^(@)=-394 kJ H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l) , DeltaG^(@)=237 kJ What is the standard free energy change for the reaction H_(2)(g)+2C(s)toC_(2)H_(2)(g) ?

The free energy change for the following reactions are given below C_(2)H_(2)(g)+(5)/(2)O_(2)(g)to2CO_(2)(g)+H_(2)O(l),DeltaG^(@)=-1234kJ C(s)+O_(2)(g)toCO_(2)(g),DeltaG^(@)=-394kJ H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l),DeltaG^(@)=-273kJ What is the standard free energy change for the reaction H_(2)(g)+2C(s)toC_(2)H_(2)(g) :-

The free energy change for the following reactions are given below C_(2)H_(2)(g)+(5)/(2)O_(2)(g)to2CO_(2)(g)+H_(2)O(l),DeltaG^(@)=-1234kJ C(s)+O_(2)(g)toCO_(2)(g),DeltaG^(@)=-394kJ H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l),DeltaG^(@)=-273kJ What is the standard free energy change for the reaction H_(2)(g)+2C(s)toC_(2)H_(2)(g) :-