" 3.3."(x-5)(x-6)=(25)/((24)^(2))

Solve : (x-5)(x-6)=25/((24)^2)

5^(x)-24=(25)/(5^(x))

(x^(24))/(x^(25))

If x=3 and y=-1, find the values of each of the using identity: ((5)/(x)+5x)((25)/(x^(2))-25+25x^(2))

(x+5)/(2)+(x-5)/(3)=(25)/(6)

The coefficient of x^(324) in the expansion of (x+1)(x2)^(2)(x+3)^(3)(x4)^(4)......(x24)^(24)(x+25)^(25) is

The coefficient of x^(24) in ((25C_(1))/(25C_(0))-x)(x-2^(2)(25C_(2))/(25C_(1))(x-3^(2)(25C_(3))/(25C_(2)))(x-4^(2)(25C_(4))/(25C_(3)))......,(x-25^(2)(25C_(25))/(25C_(24))) is equal to 2925

12^(5x-2)=(24sqrt3)^(3-x^2)

3x+(6)/(5)=6x+(3)/(25)

(x^2+x-6)(x^2-3x-4)=24