Two forces `vec(F)_(1)=500N` due east and `vec(F)_(2)=250N` due north have their common initial point. `vec(F)_(2)-vec(F)_(1)` is

Two forces vec(F_(1)) and vec(F_(2)) are acting at right angles to each other , find their resultant ?

If three forces vec(F_(1)),+vec(F_(2))andvec(F_(3)) are represented by three sides of a triangle and vec(F_(1))+vec(F_(2))=-vec(F_(3)) , then these three forces are concurrent forces and satisfy the condition for equilibrium . Statement II : A triangle made up of three forces vecF_(1),vecF_(2)andvecF_(3) as sides taken in the same order ,satisfy the condition for translatory equilibrium . In the light of the above statements ,choose the most appropriate answer from the options given below :

Which of the figure's six arrangements correctly show the vector addition of forces vec(F)_(1) and vec(F)_(2) to yield the third vector, which is meant to represent their net force vec(F)_("net") ?

Two forces vec(F)_(1) = 3hati +4hatj and vec(F)_(2) = 3hatj +4hatk are acting simultaneously at a point. What is the magnitude of the resultant force ?

A particle of m=5kg is momentarily at rest at x= at t=. It is acted upon by two forces vec(F)_(1) and vec(F)_(2) . Vec(F)_(1)=70hat(j) N. The direction and manitude of vec(F)_(2) are unknown. The particle experiences a constant acceleration, vec(a) ,in the direction as shown in (figure) Neglect gravity. a.Find the missing force vec(F)_(2) . b. What is the velocity vector of the particle at t=10 s ? c. What third force, vec(F)_(3) is required to make the acceleration of the particle zero? Either give magnitude and direction of vec(F)_(3) or its components.

A particle of m=5kg is momentarily at rest at x= at t=. It is acted upon by two forces vec(F)_(1) and vec(F)_(2) . Vec(F)_(1)=70hat(j) N. The direction and manitude of vec(F)_(2) are unknown. The particle experiences a constant acceleration, vec(a) ,in the direction as shown in (figure) Neglect gravity. a.Find the missing force vec(F)_(2) . b. What is the velocity vector of the particle at t=10 s ? c. What third force, vec(F)_(3) is required to make the acceleration of the particle zero? Either give magnitude and direction of vec(F)_(3) or its components.

A slab is subjected to two forces vec F_(1) and vec F_(2) of same magnitude F as shown in the figure . Force vec F_(2) is in XY-plane while force F_(1) acts along z-axis at the point (2 vec I + 3 vec j) .The moment of these forces about point O will be :

A slab is subjected to two forces vec F_(1) and vec F_(2) of same magnitude F as shown in the figure . Force vec F_(2) is in XY-plane while force F_(1) acts along z-axis at the point (2 vec I + 3 vec j) .The moment of these forces about point O will be :

STATEMENT -1 : Net force on a particle w.r.t an inertial frame does notdepend on the velocity of the intertial frame. , STATEMENT - 2 : If net force on A is vec(F)_(A) and net force on B is vec(F)_(B) then force on A w.r.t B is (ven(F)_(A) - vec(F)_(B)) . STATEMENT - 2 : If acceleration of A is vec(a)_(A) and acceleration of B is vec(a)_(B) then, the acceleration of A w.r.t B is ( vec(a)_(A) - vec(a)_(B))

STATEMENT -1 : Net force on a particle w.r.t an inertial frame does notdepend on the velocity of the intertial frame. , STATEMENT - 2 : If net force on A is vec(F)_(A) and net force on B is vec(F)_(B) then force on A w.r.t B is (ven(F)_(A) - vec(F)_(B)) . STATEMENT - 2 : If acceleration of A is vec(a)_(A) and acceleration of B is vec(a)_(B) then, the acceleration of A w.r.t B is ( vec(a)_(A) - vec(a)_(B))