If the abscissae of points A, B are the ...

If the abscissae of points A, B are the roots
of the equation, `x^(2) + 2ax - b^(2) = 0 ` and ordinates of A, B are roots of `y^(2)+2py- q^(2) = 0`, then find the equation of a circle for which `overline(AB)` is a diameter.

Similar Questions

Explore conceptually related problems

If the abscissae of points A, B are the roots of the equation x^(2) + 2ax -b^(2) =0 and ordinates of A, B are roots of y^(2) + 2py -q^(2) =0 , then find the equation of the circle for which AB is a diameter.

The roots of the equation x^(2)+2ax+a^(2)+b^(2)=0 are

The abscissae of two points Aand B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of y^(2)+2py-q^(2)=0 then the distance AB in terms of a,b,p,q is

The abscissa of two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of y^(2)+2py-q^(2)=0 then the distance AB in terms of a,b,p,q is

The roots of the equation x^2+ax+b=0 are

The roots of the equation x^(2) + ax + b = 0 are "______" .

The abscissa of A and B are the roots of the equation x^(2) + 2ax -b^(2) =0 and their ordinates are the roots of the equation y^(2) + 2py -q^(2) = 0. The equation of the circle with AB as diameter is

The abscissae of two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinate are the roots fo the equations y^(2)+2py-q^(2)=0 then the radius of the circle with AB as diameter is

If the abscissae of points A, B are the roots of the equation, `x^(2) + 2ax - b^(2) = 0 ` and ordinates of A, B are roots of `y^(2)+2py- q^(2) = 0`, then find the equation of a circle for which `overline(AB)` is a diameter.

Similar Questions

Recommended Questions

If the abscissae of points A, B are the roots
of the equation, `x^(2) + 2ax - b^(2) = 0 ` and ordinates of A, B are roots of `y^(2)+2py- q^(2) = 0`, then find the equation of a circle for which `overline(AB)` is a diameter.