A battery of 3.0 V is connected to a resistor dissipating 0.5 W of power . If the terminal voltage of the battery is 2.5 V , the power dissipated within the internal resistance is :

Five equal resistors when connected in series dissipated 5 W power. If they are connected in paralle, the power dissipated will be

On giving 220 V to a resistor the power dissipated is 40 W then value of resistance is

A battery of emf 10 V and internal resistance 3Omega is connected to a resistor. The current in the circuit is 0.5 A . The terminal voltage of the battery when the circuit is closed is

A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor. The current in the circuit is 0.5 A. The terminal voltage of the battery when the circuit is closed is

A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor. The current in the circuit is 0.5 A. The terminal voltage of the battery when the circuit is closed is

Five equal resistors, when connected in seires, dissipated 5 W power, if they are conneted in parallel, the power dissipated will be

A battery of emf 10 V and internal resistance 3Omega is connected to a resistor. The current in the circuit is 0.5A. The terminal voltage of the battery when the circuit is closed is

Terminal voltage of battery of 1.25 V and emf of battery" 1.5V , so internal resistance of battery is ...... Omega .

A battery has an emf of 12 V and connected to a resistor of 3Omega . The current in the circuit is 3.93 A. Calculate (a) terminal voltage and the internal resistance of the battery (b) power delivered by the battery and power delivered to the resistor.