If `sin(alpha + beta) = 1, sin(alpha - beta) = 1/2` then `tan(alpha + 2 beta) tan(2 alpha + beta)`=

If sin(alpha + beta) = 1 , sin(alpha - beta) = 1/2 , then : tan(alpha + 2beta)tan(2alpha + beta) is equal to :

If sin (alpha + beta)=1, sin (alpha- beta)= (1)/(2) , then tan (alpha + 2beta) tan (2alpha + beta) =

If sin (alpha+beta ) =1 , sin (alpha-beta ) =1//2 " then " tan (alpha +2beta ) tan(2alpha+beta ) =

If sin (alpha+beta)=1, sin (alpha-beta)=1/2 , then tan (alpha+ 2beta). tan (2 alpha+beta) is equal to :

If : sin (alpha + beta)=1 and sin (alpha-beta)=(1)/(2), "then" : tan (alpha+2beta)*tan(2alpha+beta)=

If : sin (alpha + beta)=1 and sin (alpha-beta)=(1)/(2), "then" : tan (alpha+2beta)*tan(2alpha+beta)= A)-1 B)0 C)1 D)2

If 3sin beta = sin(2alpha + beta) , then tan(alpha + beta)-2tan alpha is: