7xy=log y+Cquad :quad y'=(y^(2))/(1-xy)(xy!=1)

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: xy=log y+Cvdotsy'=(y^(2))/(1-xy)(xy!=1)

verify that the given functions(explicit or implicit) is a solution of the corresponding differential equation : xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)

Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation: xy = logy +C : y' = (y^2/(1-xy)) (xy ne 1)

Verify that the given function (explicit or implicit) is a solution of the correseponding differential equation : xy = log y + c : y'= y^2/(1-xy) (xy ne 1)

Verifty that the given function (explicit or implict) is a solution of the corresponding differential equation: xy=logy+C : y'=y^2/(1-xy)(xy ne 1)

In each of the following examples verify that its given expression is a solution of the corresponding differential equation(1) \xy=log y+c,y'=y^2/(1-xy),xy ne 1