[x^(3)-6x^(2)+3x+10quad x+1)],[x+1=0]

Find the greatest and least value of y= x^(3)-3x^(2) + 6x-2 on [-1,1] y is differentiable function of x and y'(x) = 3x^(2) -6x + 6= 3(x^(2) -2x+2) =3(x-1)^(2) gt 0 .

Maximize z = x_(1) + 3x_(2) Subject to 3x_(1) + 6x_(2) le 8 5x_(1) + 2x_(2) le 10 and x_(1), x_(2) ge 0

Given 3x^(2) +x=1 , find the value of 6x^(3) - x^(2) -3x + 2010 .

9x^2-6x+1 -: (3x-1)

Solve: (x+2)(3x +4) -6x = 10 + (3x +2)(x+1)

If x^(4) - 3x^(2) - 1 = 0 , then the value of (x^(6)-3x^(2)+(3)/(x^(2))-(1)/(x^(6))+1) is :