A motor car running at the rate of `7ms^(1)` can be stooped by applying brakes in `10m` Show that total resistance to the motion when brakes are on is one fourth of the weight of the car .

A motor car running at the rate of 7 "m.s"^(-1) can be stopped by its brakes in 10 m. Prove that total resistance to the motion when brakes are on is one fourth of the weight of the car.

A motor car running at the rate of 7 m s^-1 can be stopped by its brakes in 10m.Prove that total resistance to the motion when braeks are on is one-fourth of the weight of the car.

A motor car running at the rate of 7m//s can be stopped by brakes in 10m . Prove that the total resistance to the motion when the brakes are on is one-fourth of the weight of the car.

A motor car running at the rate of 7 m/s can be stopped by it's brakes in 10 meters. Prove that the total resistance to car's motion, when the brakes are on is one quarter of the weight of the car.

A one-ton car moves with a constant velocity of 15 ms^(–1) on a rough horizontal road. The total resistance to the motion of the car is 12% of the weight of the car. The power required to keep the car moving with the same constant velocity of 15ms^(–1) is [Take g=10ms^(-2) ]

A car in motion is brought to rest by applying brakes. What is the direction of the above identified force with respect to the motion of the car?

A motor car of mass 300 kg is moving with a velocity of 25 ms^(-1) , by applying brakes the car was brought to rest in a distance of 15 m. The force of retardation in Newton is

A car moving at 40 km/h is to be stopped by applying brakes in the next 4 m. If the car weighs 2000 kg, what average force must be applied on it?

A motor car moving with a uniform speed of 20 m/sec comes to stop on the application of brakes after travelling a distance of 10m, its deceleration is