`(3)/(7)+x=(17)/(7)`

If 8tan x=15, then sin x-cos x is equal to (8)/(17)( b) (17)/(7)( c) (1)/(17) (d) (7)/(17)

If A = [[x, -2],[3, 7]] and A^(-1) = [[(7)/(34), (1)/(17)],[(-3)/(34), (2)/(17)]] , then the value of x is

x+7-(8x)/(3)=(17)/(6)-(5x)/(2)

X+7-(8X)/(3)=(17)/(6)-(5X)/(2)

Solve the following equations. frac(3)(7) + x = frac(17)(7)

The range of the function f(x)=(x^2+x+2)/(x^2+x+1),x in R , is (1,oo) (b) (1,(11)/7) (1,7/3) (d) (1,7/5)

The range of the function f(x)=(x^2+x+2)/(x^2+x+1),x in R , is (1,oo) (b) (1,(11)/7) (1,7/3] (d) (1,7/5)

If x is real, the maximum value of (3x^(2)+9x+17)/(3x^(2)+9x+7) is (a) (17)/(7) (b) (1)/(4) (c) 41 (d) 1

If x is real, the maximum value of (3x^(2)+9x+17)/(3x^(2)+9x+7) is (a) (17)/(7) (b) (1)/(4) (c) 41 (d) 1

Find the zeroes of the function f(x) = (X-17) (x-7)