Home
Class 11
MATHS
The equation of a circle of radius 1 tou...

The equation of a circle of radius 1 touching the circles `x^2+y^2-2|x|=0` is `x^2+y^2+2sqrt(2)x+1=0` `x^2+y^2-2sqrt(3)y+2=0` `x^2+y^2+2sqrt(3)y+2=0` `x^2+y^2-2sqrt(2)+1=0`

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of a circle of radius 1 touching the circles x^2+y^2-2|x|=0 is (a) x^2+y^2+2sqrt(2)x+1=0 (b) x^2+y^2-2sqrt(3)y+2=0 (c) x^2+y^2+2sqrt(3)y+2=0 (d) x^2+y^2-2sqrt(2)+1=0

The equation of a circle of radius 1 touching the circles x^2+y^2-2|x|=0 is (a) x^2+y^2+2sqrt(2)x+1=0 (b) x^2+y^2-2sqrt(3)y+2=0 (c) x^2+y^2+2sqrt(3)y+2=0 (d) x^2+y^2-2sqrt(2)+1=0

The equation of a circle of radius 1 touching the circles x^2+y^2-2|x|=0 is (a) x^2+y^2+2sqrt(2)x+1=0 (b) x^2+y^2-2sqrt(3)y+2=0 (c) x^2+y^2+2sqrt(3)y+2=0 (d) x^2+y^2-2sqrt(2)+1=0

The equation of a circle of radius 1touching the circles x^(2)+y^(2)-2|x|=0 is x^(2)+y^(2)+2sqrt(2)x+1=0x^(2)+y^(2)-2sqrt(3)y+2=0x^(2)+y^(2)+2sqrt(3)y+2=0x^(2)+y^(2)-2sqrt(2)+1=0

Equation of a circle of radius 2 and touching the circles x^2+y^2-4|x|=0 is x^2+y^2+2sqrt(3)y+2=0 x^2+y^2+4sqrt(3)y+8=0 x^2+y^2-4sqrt(3)y+8=0 none of these

The equation of a circle of radius 1 touching the circles x^2 + y^2 - 2 |x| = 0 is: (A) x^2 + y^2 + 2sqrt(3x) - 2 = 0 (B) x^2 + y^2 - 2sqrt(3)y+2=0 (C) x^2 + y^2 + 2sqrt(3) y + 2 = 0 (D) x^2 + y^2 + 2 sqrt(3) x + 2 = 0

Equation of a circle of radius 2 and touching the circles x^(2)+y^(2)-4|x|=0 is x^(2)+y^(2)+2sqrt(3)y+2=0x^(2)+y^(2)+4sqrt(3)y+2=0x^(2)+y^(2)-4sqrt(3)y+8=0 none of these

The equation to the tangent to the circle x^2+y^2+2x-1=0 at (-1,sqrt2) is

sqrt(2)x + sqrt(3)y=0 sqrt(5)x - sqrt(2)y=0