Let `x_(1),x_(2),…..,x_(n)` be is an AP . If `x_(1)+x_(4)+x_(9)+x_(11)+x_(20)+x_(22)+x_(27)+x_(30)= 272 ,` then `x_(1)+x_(2)+x_(3)+…+x_(30)` is equal to

Let x_(1), x_(2), …… , x_(n) be in an A.P. If x_(1) + x_(4) + x_(9) + x_(11) + x_(20) + x_(22) + x_(27) + x_(30) = 272 , then x_(1) + x_(2) + x_(3) + ...... + x_(30) is equal to

Let x _(1), x _(2), ..., x _(n) be in an AP. If x _(1) + x _(4) + x _(9) + x_(11) + x _(20) + x _(22) + x _(27) + x _(30) = 272, then x _(1) + x _(2) + x_(3) + ...+ x _(30) is equal to

If x_(1),x_(2),….x_(20) are in H.P then x_(1)x_(2)+x_(2)x_(3)+….+x_(19)x_(20) =

If x_(1),x_(2),….x_(20) are in H.P then x_(1)x_(2)+x_(2)x_(3)+….+x_(19)x_(20) =

x_(1),x_(2),x_(3)"…." are in A.P. If x_(1)+x_(7)+x_(10)=-6 and x_(3)+x_(8)+x_(12)=-11 , then x_(3)+x_(8)+x_(22) =

If x_(1),x_(2),x_(3)...x_(n) are in H.P,then prove that x_(1)x_(2)+x_(2)x_(3)+xx x-3x_(4)+...+x_(n-1)x_(n)=(n-1)x_(1)x_(n)

If 4, x_(1), x_(2), x_(3), 28 are in AP then x_(3) = ?

Let x_(1),x_(2),x_(3),.... be terms of an AP, if (x_(1)+x_(2)+...+x_(n))/(x_(1)+x_(2)+...+x_(m))=(n^(2))/(m^(2)).(n!=m)," then "(x_(8))/(x_(23))=?

Let x_(1),x_(2),... be positive integers in A.P.,such that x_(1)+x_(2)+x_(3)=12 and x_(4)+x_(6)=14 then x_(5) is

If x_(1),x_(2),x_(3),......x2_(n) are in A.P, then sum_(r=1)^(2n)(-1)^(r+1)x_(r)^(2) is equal to