`(cosA cosec A-sinAsecA)/(cosA+sinA)=cosecA-secA`

Prove: (cosAcosecA-sinAsecA)/(cosA+sinA)=cosecA-secA

Prove the following identity, where the angles involved are acute angles for which the expressions are defined. (v) (cosA-sinA+1)/(cosA+sinA-1)=cosec A+cotA

Prove that : (cosec A-sin A ) (sec A-cos A)=sinA cosA

Prove that (cosA-sinA+1)/(cosA+sinA-1) = cosecA+cotA

(cos2A)/(secA)+(sin2A)/(cosecA)=cosA

(cos2A)/(secA)+(sin2A)/(cosecA)=cosA

Prove that (cosA-sinA+1)/(cosA+sinA-1) =cosec A+ cot A using the identity cosec^(2)A=1+cot^(2)A .

Prove that (cosA-sinA+1)/(cosA+sinA-1) =cosec A+ cot A using the identity cosec^(2)A=1+cot^(2)A .

Prove the following identities. where the angles involved are acute angles for which the expressions are defined. (cosA-sinA+1)/(cosA+sinA-1)=cosecA+cotA , using the identity cosec^(2)A=1+cot^(2)A .

((cosA+sinA)/(cosA-sinA))-((cosA-sinA)/(cosA+sinA))=