The sum of ` 0.2 +0.22+0.222+ …` to n terms is equal to

0.2 + 0.22 + 0.222+ …. upto n terms is equal to

Find 2 + 22 + 222 + 2222 ……. Upto n terms

If the sum of the first n terms of a sequence is equal to √ (3/ 2) ( n^ 2 − n ) , then the sum of the squares of these terms is equal to

Find the sum of 2+0.2+0.02+0.002+... upto 20 terms

Find the sum of the series 0.3+ 0.33 + 0.333+ ……to n terms

Find the sum of the series 0.6 +0.66 +0.666+ ... to the n terms

Find the sum of the first n terms of the series: 0.2 + 0.22 + 0.222+ ....n - terms