Let `f: RrarrR` and `g: RrarrR` be defined by `f(x)=x+1` and `g(x)=x-1.` Show that `fog=gof=I_Rdot`

Let f:R rarr R and g:R rarr R be defined by f(x)=x+1 and g(x)=x-1. Show that fog =gof=I_(R)

Let f:R rarr and g:R rarr R be defined by f(x)=x+1 and g(x)=x-1. Show that fog =gof=I_(R) .

Let f: R->R and g: R->R be defined by f(x)=x+1 and g(x)=x-1. Show that fog=gof=I_Rdot

Let f:R rarr R and g:R rarr R be defined by f(x)=x^(2) and g(x)=x+1. Show that fog != gof

Let f: Rveca n dg: RvecR be defined by f(x)=x+1a n dg(x)=x-1. Show that fog=gof=I_Rdot

Let f:RrarrR be defined as f(x)=2x .

Let f: R->R and g: R->R be defined by f(x)=x^2 and g(x)=x+1 . Show that fog!=gofdot

Let f: R->R and g: R->R be defined by f(x)=x^2 and g(x)=x+1 . Show that fog!=gofdot

Let f: RvecR and g: RvecR be defined by f(x)=x^2 and g(x)=x+1. Show that fog!=gofdot

Let f: Rrarr R and g: RrarrR be defined by f(x) = x^2 and g(x) = x + 1 . show that gof is not equal to fog .