`sin2 5^(@)cos6 5^(@)+cos2 5^(@)sin6 5^(@)`

The value of (cos ^(6)5^(@)-15 cos ^(4) 5^(@) sin ^(2)5^(@)+15 cos ^(2)5^(@)sin ^(4) 5^(@)-sin ^(6)5^(@)) is equal to-

(sin2^(@)+sin4^(@)+sin6^(@)+sin8^(@))/(cos1^(@)*cos2^(@)*cos5^(@))=

A=cos20^(@) - sin 20^(@) ,B=cos100^(@) + sin100^(@) , C= cos""(5pi)/6+ sin""(2pi)/3 then the ascending order is

sin5A=5cos^(4)A sin A-10cos^(2)A sin^(3)A+sin^(5)A

Prove that, sin5A=5cos^(4)AsinA-10cos^(2)Asin^(3)A+sin^(5)A

sin 10 x = 2 sin 5x cos 5x

Solve 4 cos^(2)x+6 sin^(2)x=5 .

Solve 4 cos^(2)x+6 sin^(2)x=5 .

Solve 4 cos^(2)x+6 sin^(2)x=5 .