Home
Class 12
CHEMISTRY
1.4 g of acetone dissolved in 100 g of b...

`1.4 g` of acetone dissolved in `100 g` of benzene gave a solution which freezes at `277.12 K`. Pure benzene freezes at `278.4 K`.`2.8` of solid `(A)` dissolved in `100 g` of benzene gave a solution which froze at `277.76 K`. Calculate the molecular mass of `(A)`.

Promotional Banner

Similar Questions

Explore conceptually related problems

The boiling point of benzene is 353.23 K. When 1.80g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute.

1.250 g of naphthalene was dissolved in 60 cm3 of benzene and freezing point of the solution was found to be 277.515 K while that of benzene 278.495 K. Density of benzene is 0.880 g cm^(-3) Kf = 5.1 K mol^(-1) kg. Calculate the molecular weight of naphthalene.

2g of a non-electrolyte solute dissolved in 100g of benzene lowered the freezing point of benzene by 0.40 K. find the molar mass of the solute.

The boiling point of benzene is 353.2 K .When 1.8 g of a non - volatile solute was dissolved in 90 g benzene the boiling point was raised to 354.1 K . Calculate the molecular mass of the solute. ( K_b of benzene = 2.53 K kg mol^-1 )

The boiling point of benzene is 353.23K. When 1.80g of a non-volatile solute was dissolved in 90g of benzene, the boiling point is raised to 354.11K. Calculated the molar mass of the solute k_b for benzene is 2.53K kg mol^(-1)

The boiling a point of benzene is 353.23K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. K_(b) for benzene is 2.53 K kg mol^(-1) .