Radius of current carrying coil is 'R'. Then ratio of magnetic fields at the centre of the coil to the axial point, which is `Rsqrt(3)` distance away from the centre of the coil :-

The magnetic field at the centre of the current carrying coil

The magnetic field at the centre of current carrying coil is

A circular coil of 100 turns has a radius of 10 cm and carries a current of 5A. Calculate the magnetic field (a) at the centre of the coil (b) at a point on the axis of the coil at a distanceof 5cm from the centre of the coil.

The ratio of the magnetic field at the centre of a current carrying coil of the radius a and at distance 'a' from centre of the coil and perpendicular to the axis of coil is

A circular coil of 120 turns has a radius of 18cm and carries a current of 3*0A . What is the magnitude of the magnetic field (i) at the centre of the coil (ii) at a point on the axis of the coil at a distance from the centre equal to the radius of the coil?

A circular current-carrying coil has a radius R . The distance from the centre of the coil, on the axis, where B will be 1//8 of its value at the centre of the coil is

A circular current carrying coil has a radius R. The distance from the centre of the coil on the axis where the magnetic induction will be (1)/(8) th to its value at the centre of the coil, is

Ratio of magnetic field at the centre of a current carrying coil of radius R and at a distance of 3R on its axis is