A ball is thrown vertically upwards from the top of a tower with a velocity of 10m/s. If the ball falls on the ground after 5 seconds, the height of the tower will be? (use g=10m/`s^(2)`)

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.

A ball is thrown vertically upward from the top of a tower with a speed of 100 m/s. It strikes the pond near the base of the tower after 25 second. The height of the tower is

A ball is thrown vertically upwards from the top of a tower at 4.9 ms^(-1) . It strikes the pond near the base of the tower after 3 seconds . The height of the tower is

A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower,It hits the ground after some time with a velocity of 80m/s .The height of the tower is : (g=10m/g^(2))

A ball is thrown upwards from the top of a tower 40 m high with a velocity of 10 m//s. Find the time when it strikes the ground. Take g=10 m//s^2 .

A ball is thrown vertically upwards from the top of a tower of height 60 m with a speed of 20 m//s. (i) The ball strikes the ground after 6 s (ii) The ball strikes the ground with speed 40 m//s (iii) The distance of ball above the ground after 5 s is 35 m The maximum height attained by ball above the ground is 80 m

A ball projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of 6 s and the ball reaches the ground after 12 s . The height of the tower is (g = 10 m//s^2) :