If x=log2 and y=log3, then a+bx+cy=[log1...

If `x=log2` and `y=log3,` then `a+bx+cy=[log1+log(1+3)+log(1+3+5)+....+log(1+3+5+....,+19)]- 2 [log1+log2+log3+.....+log7],` where `a,b` and `c` are positive integers. The value of `2a+3b+5c` is equal to (where `log a=log_(10)a)`

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If `x=log2` and `y=log3,` then `a+bx+cy=[log1+log(1+3)+log(1+3+5)+....+log(1+3+5+....,+19)]- 2 [log1+log2+log3+.....+log7],` where `a,b` and `c` are positive integers. The value of `2a+3b+5c` is equal to (where `log a=log_(10)a)`

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