The product of first three terms of a G.P. is 1000. If 6 added to its second term and 7 added to its third term, the terms become in A.P. Find the G.P.

The product of first three terms of a G.P. is 1000 . If we add 6 to its second term and 7 to its third term, the resulting three terms form an A.P. Find the terms of the G.P.

The product of first 3 terms of a GP is 1000. If 6 terms to the second term and 7 is added to the third term, the terms become an AP. Find the terms of the GP.

The product of first three terms of a G.P. is 1000. If we add 6 to its second term and 7 to its 3rd term, the three terms form an A.P. Find the terms of the G.P.

The product of first 3 terms of a GP is 1000. If 6 terms to the second term and 7 is added to the third term, the terms become an AP. Find the second term of GP.

The product of three numbers in G.P. is 512. If 8 be added to the first, and 6 to the second, then these two sums and the third term form an A.P., find the numbers.

The product of three consecutive terms of a G.P. is 512. If 4 is added to each of the first and the second of these terms, the three terms now form an A.P. Then the sum of the original three terms of the given G.P. is

The 4th term of a G.P. is square of its second term and the first term is -3. Find its 7th term.

The 4th term of a G.P. is square of its second term, and the first term is -3. Determine its 7th term.

The first term of a G.P. is -3 and the square of the second term is equal to its 4^(th) term. Find its 7^(th) term.

The 4th term of a G.P. is square of its second term, and the first term is-3. Determine its 7th term.