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Let the line (x-2)/3=(y-1)/(-5)=(z+2)/2 ...

Let the line `(x-2)/3=(y-1)/(-5)=(z+2)/2` lie in the plane `x""+""3y""alphaz""+beta=""0` . Then `(alpha,beta)` equals (1) `(6,""""-17)` (2) `(-6,""7)` (3) `(5,"" -15)` (4) `(-5,""5)`

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