If `Delta ABC~Delta DEF` such that `2AB=DE and BC=6 cm` find EF.

Given two triangles ABC and DEF. If Delta ABC ~ Delta DEF, 2AB = DE and BC = 8 cm, then find the length of EF.

If Delta ABC ~ Delta DEF such that AB = 1.2 cm and DE = 1.4 cm, the ratio of the areas of Delta ABC and Delta DEF is :

If triangle ABC is similar to triangle DEF such that 2AB = DE and BC = 8 cm then EF is .

Delta ABC~DeltaDEC such that ar(Delta ABC)=64 cm^(2) and ar (Delta DEF)=169 cm^(2) . If BC=4 cm , find EF.

If Delta ABC ~ Delta DEF such that area of Delta ABC " is " 9 cm^(2) and the area of Delta DEF " is " 16 cm^(2) and BC=2.1 cm. Find the length of EF.

If Delta ABC and Delta DEF are similar and 2AB = DE , BC = 8 cm , then calculate EF.

If Delta ABC is similar to Delta DEF such that BC = 4cm, EF = 5 cm and are a of Delta ABC = 64 cm^(2) find are a of Delta DEF .

If Delta ABC is similar to Delta DEF such that BC = 3 cm, EF = 4 cm and area of Delta ABC = 54 cm^(2) , then the area of Delta DEF is :

If Delta ABC is similar to Delta DEF such that BC=3 cm, EF=4 cm and area of Delta ABC=54 cm^(2) . Find the area of Delta DEF .