If in the previous problem, the particle travels `9//25` of the distance in its last second, find the time of fall and the height of the tower.

A particle is dropped the top of a tower. Its displacement in the first three seconds and in the last second is the same. Find the height of the tower.

If body travels half of its path in the last second of its fall from rest, find the time and height of its fall.

If body travels half of its path in the last second of its fall from rest, find the time and height of its fall.

If body travels half of its path in the last second of its fall from rest, find the time and height of its fall.

A body falls freely from the top of a tower. It covers 36 % of the total height in the last second before striking the ground level. The height of the tower is

A body dropped from the top of a tower covers 7/16 of the total height in the last second of its fall. The time of fall is

A body dropped from the top of a tower covers 7/16 of the total height in the last second of its fall. The time of fall is

A stone dropped from the top of a tower travels (5)/(9) th of the height of tower during the last second of fall. Height of the tower is: (Take g = 10 m//s^(2) )